13100

13100 is the natural number that comes after 13099 and before 13101. It is an even and composite number, with prime factorization 13100 = 2^2 × 5^2 × 131, since 131 is itself a prime.

Because it ends in two zeros, 13100 is divisible by 100 (and thus by 4, 5, 10, 20, 25, and 50 as well). It is not divisible by 8, since the last three digits (100) are not a multiple of 8. The number has 18 positive divisors, which follows from its factorization: (2+1)(2+1)(1+1) = 18.

The sum of all divisors of 13100 is sigma(13100) = 7 × 31 × 132 = 28644. Therefore the sum of proper divisors is 28644 − 13100 = 15544, which exceeds 13100. Consequently, 13100 is an abundant number.

In mathematical use, 13100 serves as an ordinary example of a composite, highly divisible number with a nontrivial factorization. It does not have widely noted special significance beyond its standard arithmetic properties, such as divisibility, factorization, and divisor sums. Its rounded form with trailing zeros makes it resemble a common multiple of 100, a feature that can arise in problems involving multiples, divisibility rules, and divisor calculations.

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